A particle is moving with velocity v = t3 - 6t2 + 4, where v is
in m/s andt is in seconds. At what time will the velocity be
maximum/minimum and what is it equal to?
Answers
Answered by
1
Explanation:
t3-6t2+4
=3t2-12t (here 4 is constant so it become 0
=9t-12 ( now 12 also become 0 )
= 9 ans.
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