Physics, asked by omkarajadhav123, 1 month ago

A particle is oscillating in SHM. What fraction of total energy is kinetic when the particle is at A/2 from the mean position (A is the amplitude of oscillation).​

Answers

Answered by llXxDramaticKingxXll
6

Refer to the attachment please

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Answered by soniatiwari214
1

Concept:

  • Simple Harmonic Motion
  • Conservation of mechanical energy

Given:

  • The particle is at a distance of A/2 from the mean position
  • A is the amplitude of the oscillation

Find:

  • The fraction of total energy which is kinetic

Solution:

v is the velocity of the particle and w is the angular velocity of the particle

v =w \sqrt{A^{2} - y^{2} }

Total energy E

E = 1/2 mw^{2} A^{2}

Kinetic energy at A/2

KE = 1/2mv^{2} \\KE = 1/2mw^{2} (A^{2} -y^{2} )

KE/E = (A²-y²)/A²

y = A/2

KE/E = 3/4

3/4 of the total energy is kinetic.

#SPJ3

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