Question

A particle is performing circular motion with angular speed 50 revolutions per minute if linear speed is 6.28 metre per second then find out distance of the particle from axis of radius?​

Answer 1

Answer:

1.2m

Explanation:

Given

W = 50 Revolutions per Minute

V = 6.28 m/s

To find

r = ???

Well first we need to contact convert the unit revolutions per minute into radian per second and

We know that

$\boxed{W = \frac{2\pi \: N}{t} }$

$= > W = \frac{(2\pi)( \cancel50)}{ \cancel60} \\ = > W = \frac{ \cancel2\pi \times 5}{ \cancel6} \\ = > W = \frac{5\pi}{3}rad/sec$

Now we know that

$\boxed{v = r \times W} \\ = > r = \frac{v}{W}$

On putting Values

$= > r = \frac{6.28}{ \frac{5\pi}{3} } \\ = > r = \frac{ \cancel6.28 \times 3}{5 \times \cancel3.14} \\ = > W = \frac{6}{5} \\ = > \huge \boxed{W = 1.2m}$

Therefore

Distance of the particle from the axis of radius or Generally radius will be 1.2m.

Answer 2

Answer:

: Solution :

Angular speed = 50 revolutions

Linear speed = 6.28 metre

W= 2π N

t

W= (2π) (50

60

W = 2π × 5

6

W = 5π = Radius /Second

3

Formula :

U = R × W

R = 6.28

5π

3

R= 6.28 × 3

5 × 3.14

W = 6 = 1.2m

5

W = 1.2m

Answer = 1.2m