Question

A particle is performing linear SHM of amplitude what fraction of the total energy is kinetic when the displacement is half the amplitude​

Answer 1

Answer:

sorry dont know answer

Answer 2

Answer:

ANSWER

Total energy of particle executing simple harmonic motion is,

E=21mω2A2

Therefore, kinetic energy at position is,

K=21mω2(A2−V2)

Kinetic energy at position half the amplitude of oscillation is,

K=21mω2[A2−(2A)2]

=21mω2(43A2)

K=43E

P.E=E−K=E−43E=4E

Ratio=EP.E=4E/4=0.25

Now, Potential energy will be 0.25 of the total energy.

Explanation: