A particle is performing shm according to the equation x=(3 cm) sin (2π18t+30∘), where t is in seconds. the distance travelled by the particle in 39 s is
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angular frequency omega=2π18, so frequency = 18, thus time period T=1/18.
So number of trips in 39 secs= 39/1/18=39*18=702
Distance travelled in each trip=3*4=12cm or 0.12m
So total distance = 702*0.12m = 84.24m
So number of trips in 39 secs= 39/1/18=39*18=702
Distance travelled in each trip=3*4=12cm or 0.12m
So total distance = 702*0.12m = 84.24m
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