Question

A particle is performing SHM along a path of length 16 cm if its maximum velocity is 12.56 cm per second calculate its period​

Answer 1

Answer:

Velocity v = ω√(A2 - x2) and acceleration = ω2x .Given, ω√(A2 - x2) = ω2x or √(A2 - x2) = ω x Given, T = 2π/√(3) and ω = 2π/T ...

16 x 12.56vm = 120?