Question

A particle is performing simple harmonic
motion with amplitude of 4 cm and time
period of 12 s. The ratio between timę taken
by it in going from its mean position to 2 cm
and from 2 cm to extreme position is
(A) 1
(B) 113
(C) 1/4
D) 1/2​

Answer 1

Answer:

1 I hope you understand this is answer

Answer 2

Answer:

D) 1/2

Explanation:

ω=2πT =2π 12= π6rod sec

(for y=2cm)2=4(sinπ6t1)

By solving t1=1 sec(For y=4cm)

t2=3sec

So time taken by particle from 2cm to extreme position is t2-t1=2sec Hence required ratio will be = 1/2