A particle is performing uniform circular motion with speed πm/s. If radius circular path is 2m then magnitude of average velocity of particle in time interval,∆ t= 1.5 second is
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In uniform circular motion, angular velocity () is a vector quantity and is equal to the angular displacement (Δ, a vector quantity) divided by the change in time (Δ). Speed is equal to the arc length traveled (S) divided by the change in time (Δ), which is also equal to ||R.
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