Question

A particle is placed on a rough horizontal circular table rotating with a
constant angular speed of rad/sec. It comes to rest relative to table at a
distance of 0.5 m from the axis of rotation. Then the value of mew
between
particle and table surface is ___* 10inverse1​

Answer 1

Answer:

Explanation: here we have to find out the value of co efficient of friction

Answer 2

Thus the value of u is 0.5 or 5 x 10^-1

Explanation:

Given data:

• Initial angular speed of particle ω = π / s
• Distance of particle from center is r = 0.5 m

If particle is at rest relative to table then friction force is providing centripetal acceleration to hang in there

Thus

μg = ω^2 . r

μ x 9.8 = (π)^2 x 0.5

μ  = 4.93 / 9.8

μ  = 0.5

Thus the value of u is 0.5 or 5 x 10^-1