Question

a particle is placed on a rough horizontal circular table rotating with a constant angular speed of pie rad/sec it comes to rest relative to table at a distance of 0.5 m from the axis of rotation the the value of u between particle and the surface is

Answer 1

Answer:

u884g6776hhcbuccchilmo

Answer 2

Answer:

Explanation:

Given

Initial angular speed of particle $\omega =\pi \rad/s$

distance of particle from center is $r=0.5\ m$

If particle is at rest relative to table then friction force is providing centripetal acceleration to hang in there

thus

$\mu g=\omega ^2\cdot r$

$\mu \times 9.8=(\pi )^2\cdot 0.5$

$\mu =\dfrac{4.93}{9.8}$

$\mu =0.503$