Question

A particle is projected at 60 degree to the horizontal with a kinetic energy k. the kinetic enerygy at the highest point is

Answer 1

let u be the initial velocity.
∴ initial kinetic energy is K = (1/2)mu²
at the maximum height velocity is u cos60 = (u/2)
∴ kinetic energy at the maximum height is KE=(1/2)m(u/2)²
                                                                        =(1/4)k. Hope it will help you

Answer 2

Explanation:

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