Question

A particle is projected at an angle 60 degree with speed 10 root 3 metre per second from the point

a.at the same time the wedge is made to move with a speed 10 root 3 metre per second towards right then the time after which the particles will strike the wedge is

Answer 1

Answer:2s

Explanation:We will use the concept of relative velocity....

Sorry for untidy work

Answer 2

Concept:

• Two-dimensional /projectile motion
• Conservation of momentum
• Vector components

Given:

• Angle a = 60 degrees
• Initial speed of particle = 10√3 m/s
• Speed of wedge = 10√3 m/s towards the right

Find:

• The time after which the particles will strike the wedge is

Solution:

• Assume that the particle hits the wedge at height h after some time t
• h = ut -1/2gt^2
• Along y axis, speed = 10√3 sin 60 = 15 m/s
• h = 15t-1/2 (10) t^2
• h = 15t-5t^2
• Consider the horizontal axis, speed along x-axis = 10√3 cos 60 = 5√3
• The distance covered horizontally d = 5√3 t
• tan 30 = h/d = 15t-5t^2/5√3 t
• 1/√3 = 3-t/√3
• t = 2s

The time after which the particles will strike the wedge is 2s

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