Question

A particle is projected at an angle of 45° from 8 m before the foot of a wall, just touches the top of the wall and fall on the ground on the opposite side 4 m from it .The height of wall is

Answer 1

y = xTanθ * [ 1 - x/R ]
y = 8*Tan45 * [1 - 8/(8 + 4)]
y = 8 * [1 - 8/12]
y = 8/3 m
y = 2.67 m

Height of the wall is 2.67 m

Answer 2

y = xTanθ * [ 1 - x/R ]

y = 8*Tan45 * [1 - 8/(8 + 4)]

y = 8 * [1 - 8/12]

y = 8/3 m

y = 2.67 m