Question

A particle is projected at an angle of 45degree with velocity of 9.8m/s in presence of air resistance the horizontal range can be

Answer 1

Horizontal range is given by formula. Derivation of formula can be obtained in any 11th Physics text book

R = u^2 × sin (2×theta)/g

Given theta = 45 degree

sin (2 × theta) = sin (90) =1

R = u^2/g

R =( 20 × 0)/10. (g =10 m/s^2 …approximately)

R = 40 meter….. (approximately)

Hope this may help