Question

A PARTICLE IS PROJECTED AT AN ANGLE OF 60 DEGREES TO TBE THE HORIZONTAL WITH A SPEED OF 20M/S. what is the total time of flight of the particle . 2) what is the apeed of the particle at its maximum height

Answer 1

Explanation:

let u be the initial velocity.

∴ initial kinetic energy is K = (1/2)mu²

at the maximum height velocity is u cos60 = (u/2)

∴ kinetic energy at the maximum height is KE=(1/2)m(u/2)²

=(1/4)k

Thank you

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