Question

A PARTICLE IS PROJECTED AT AN ANGLE OF 60 DEGREES TO TBE THE HORIZONTAL WITH A SPEED OF 20M/S. what is the total time of flight of the particle . 2) what is the apeed of the particle at its maximum height

Answer 1

Answer:

1) 20$\sqrt{3}$ seconds  

2) 10$\sqrt{3}$ m/s

Explanation:

1) Time of flight of a projectile motion is :

   {2usin(θ)}/g

where , u is the projected velocity , g is the acceleration due to gravity (10m/$s^{2}$) and θ is the angle made with the horizontal .

2) At max height , the vertical component of velocity is zero . So , the speed of the particle at max height is ucos(θ) .

Hope it helps ya !