Question

a particle is projected at an angle of 60 with horizontal with velocity of 100 m/s .its velocity at the heighest point is ... plz explain answer also​

Answer 1

At the highest point i.e., maximum height is H at that point the velocity of the project is taken as, v=0m/s.

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Answer 2

Answer:

50 m/s

Explanation:

As the body reaches the highest point it's vertical component of velocity decreases gradually and becomes zero.

Now it has only horizontal component which we can find it as u times cos of angle with horizontal.

which is equals to 100 * 1/2 = 50 m/s.

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