Question

A particle is projected at an angle of 60O to the horizontal with a speed of 20 m/s
Calculate (i) Total time of flight of the particle (4
(ii) Speed of the particle at its maximum height [take g = 10 m/s2]

Answer 1

Explanation:

1. Total time of the flight is given by the formula T=2usin60^o/g

=2x20x 0. 866/10

=3.84sec

2. Speed of the particle at max height is given by u=8hg/3

=8x10x20/3

=533.3metres