Question

A particle is projected at an angle or 45 degree with a velocity of 9.8 meter par second. The horizontal range will be

Answer 1

Hi dear !!!

the horizontal range formula given by =>

R = u² sin2∅ /g


=> 9.8 × 9.8 / sin90° / 9.8

=> 9.8 m


hence , the horizontal range will be 9.8 m


hope it help you dear!!!

thanks !!!

RJ

Answer 2

R=u^2 sin2 theta /g

R=(9.8)^sin90/9.8

9.8meter

......
kk