Question

A particle is projected at t = 0 from ground its velocity at t = 8sec is V = (15 i^ + 3 j^)m/s find out
(A):- velocity at Max Height
(B):- time of flight, range and maximum height​

Answer 1

Answer:

velocity = displacement / time and To find the time of flight, determine the time the projectile takes to reach maximum height. The time of flight is just double the maximum-height time. At maximum height, vy = 0. The time of flight is also determined solely by the initial velocity in the y direction and the acceleration due to gravity. and for range use An object launched into projectile motion will have an initial launch angle anywhere from 0 to 90 degrees. The range of an object, given the initial launch angle and initial velocity is found with: R=v2isin2θig R = v i 2 sin ⁡ 2 θ i g .the maximum height is given by u²/(2*g) .