Physics, asked by anuvrat77, 7 months ago

- A particle is projected from a horizontal plane with
speed u at some angle. At highest point its velocity
u/2. The maximum height of the projectile will be

Answers

Answered by mbakshi37

1

Answer:

mgH gain is loss of 3/4 KE

gH = 3/8 u square.

H = 3/8 U square/g

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