A particle is projected from a point A vertically upwards with a speed of 50 m/s and another is dropped simultaneously from B which is 200 m vertically above A. The particles cross each other after ____ seconds.
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Explanation:
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Answer: 4secs
Explanation:. According to the question there are two particles at a separation of 200 m.
Let the particle A cover a distance
' x ' while the particle B covers a distance 200-x in time t.
So the equations will be:
x=50t -5t^2. _____(i)
200 -x=5t^2(u=0)_____(ii)
Subtracting both the equations we get
200=50t
Therefore, t=4secs (Answer)
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