Question

A particle is projected from a point P (2, 0, 0)m with a velocity 10 m/s making an angle 45∫ with the horizontal. The plane of projectile motion passes through a horizontal line PQ which makes an angle of 37∫ with positive x-axis, xy plane is horizontal. The coordinates of the point where the particle will strike the line PQ is: (Take g = 10 m/s2

Answer 1

$\mathbb{\huge{\purple{HEY\:MATE}}}$

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Answer 2

Answer is in attachement

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