Question

A particle is projected from ground with speed 80 m/s at an angle 30° with horizontal from ground. the magnitude of average velocity of particle in time interval t = 2 s to t = 6 s is

Answer 1

let speed u = 80m/s and θ = 30°
∴ the horizontal velocity = u sinθ  = 40m/s
 and vertical velocity  = u cosθ =40√3m/s
if S is the distance travelled horizontally and h=
S=40√3t
h = 40t-5t²
position(t) = (40t,40t√3-gt²/2)
P = (138.56,60)
Q = (277.13,80)
average velocity =total displacement/time
$avg. velocity = \left(\begin{array}{ccc}69.28\\10\end{array}\right)$