Question

A particle is projected from ground with speed 80 m
s at an angle 30° with horizontal from ground. The
magnitude of average velocity of particle in time
interval t = 2 s to t = 6 s is [Take g = 10 m/s
(1) 40/2 m/s
(2) 40 m/s
(3) Zero
(4) 40/3 m/s
please answer correctly ​. who will give correct answer i will follow and mark answer as brainlist

Answer 1

Answer:

magnitude of average velocity of particale in time is 40/2 m/s

Answer 2

Answer:

$40\sqrt{3}$

Explanation:

USE

r= u^2sin2tita/g

to find the total distance

(80*80*$\frac{\sqrt{3} }{2}$)/10=$320\sqrt{3}$

and use

t= 2usintita/g

to find the time

(2*80*1/2)= 8

then take the answer