a PARTICLE IS PROJECTED FROM GROUND WITH SPEED 80 m/s AT AN ANGLE 30 DEGREE WITH HORIZONTAL FROM GROUND .THE MAG NITUDE OF AVERAGE VELOCITY OF PARTICLE IN TIME T=2SEC TO T=6SECS IS?
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hi bro you need to just focus on formula
it is too simple
solution
As there is no gravitational force in horizontal direction so ucos30=30×√3/2=25.7m/s, will remain same.
But as there is gravitational force in vertical direction so vertical component will change
And here initial u=usin30=30×1/2=15m/s
v=u+a×t
v= 15+(-10×1.5)=0
So after 1.5 second of flight object will be parallel to horizontal so angle will be 0° will horizontal.
it is too simple
solution
As there is no gravitational force in horizontal direction so ucos30=30×√3/2=25.7m/s, will remain same.
But as there is gravitational force in vertical direction so vertical component will change
And here initial u=usin30=30×1/2=15m/s
v=u+a×t
v= 15+(-10×1.5)=0
So after 1.5 second of flight object will be parallel to horizontal so angle will be 0° will horizontal.
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