Question

A particle is projected from ground with speed 80m/s at an angle 30 with horizontal from ground

Answer 1

For any projectile projected at an angle Ф,

The following parameters can be calculated very easily

1)

Height attained during the flight = (u² sin²Ф) /(2g)

= ( 80² sin² 30°)/ (20)

=80 m

2)

Range = (u² sin 2Ф)/(g)

= (80² sin 60°) / (10)

=160√3 m

3)

Time of flight = (2u sinФ )/g

= (2* 80 *sin 30°)/10

= 6sec

Hope this helps !!!!!!!!