A particle is projected from ground with speed 80m/s at an angle of 30 degree with the horizontal from ground. the magnitude of average velocity of particle in time interval t=2s to t=6s is
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verticle component is usin¢=40m/s
displacement at t=6==>40*6+1/2*(-10)*6*6
==>60m
displacement at t=2==>40*2+1/2*(-10)*2*2
==>60m
average velocity = (60-60)/6-2==>0m/s
displacement at t=6==>40*6+1/2*(-10)*6*6
==>60m
displacement at t=2==>40*2+1/2*(-10)*2*2
==>60m
average velocity = (60-60)/6-2==>0m/s
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