Question

A particle is projected from ground with velocity 40root2 m/s at 45* find velocity and displacement of the particle after 2s

Answer 1

Answer:

40root2 m/s at 45*A particle moves along the positive branch of the curve Y^2=2X where X=T^2/2. What is the acceleration of the particle at T=2value of -6.0m/s.

Explanation:

2s40root2 m/s at 45*