Question

A particle is projected from ground with velocity of 25 m/s. After 2 is it just clears a wall of 5 m height.Then angle of projection of the ball is

Answer 1

Answer:

theta = 30°

Explanation:

s= ut sin theta - 1/2 gt^ 2

s=5

t=2

u=25

g= 10

put these values in above equation

5=25×2 sin theta -1/2×10×2×2

so,

sin theta = 1/2

theta = 30°

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