Math, asked by telugugamerhrushi, 1 month ago

a particle is projected from point O over a large inclined plane making angke 37 to the horizontal as shown ,with the velocity v=9i+12j m/s X Y plane represents inclined plane particle is alwauh s in contact with the inclined plane and assume surface is perfectly smooth g=10m/s^2​

Answers

Answered by kiranchoudhary1107
1

x=

2g

u

2

=

2×10

10

2

=5m

As h is the perpendicular distance from the incline plane

sin37

o

=

5

3

or,

x

h

=

5

3

∴h=

5

3

×x=

5

3

×5=3m

Here range on inclined plane will be zero, as particle goes vertically upand comes back.

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Answered by sarojch1983
0

Answer:

Correct option is

A

3m

Step-by-step explanation:

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