A particle is projected from the earth surface with an initial speed of 4 km per second if the radius of the earth is 6400 km and gravitational acceleration is 9.8m/s^2 the maximum height attained by the particle is
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9.35km
Explanation:
The maximum height attained by the particle is,
h=v22g−v2R
Substituting the values, we have
h=(4×103)22×9.8−(4.0×103)26.4×106=9.35×105 m or f=9.35km
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