Question

A particle is projected from the ground at an angle 60┬░ with the horizontal that speed u= 20m/s find the radius of curvature of the path of the particle when its velocity makes an angle of 30┬░ with horizontal

Answer 1

u = 20 m/s.

Angle with horizontal = 30

Range = u²Sin2θ/g

           = 20² × Sin 60/10

           =  400 × √3/20

           = 20√3

∴ Raius = 10√3 m.

Hope it helps.