Question

A particle is projected from the ground with a kinetic energy
Eat an angle of 60° with the horizontal. Its kinetic energy at the highest point of its motion will be ​

Answer 1

Answer:At the highest point vertical component of velocity will be zero, only horizontal component will remain. Let horizontal component =u and speed of projection =U.  

u=Ucos60°=  

2

U

​  

 

Since speed is halved, kinetic energy will become one-fourth. So, kinetic energy at highest point will be  

4

E

​  

.