Question

a particle is projected from the ground with an initial velocity of 20m/s at an angle of 30 degree with the horizontal. What is the magnitude of change in velocity in 0.5 second?​

Answer 1

Answer:

5 m/s

Explanation:

Hey,

The solution of your query is as following..

=> Here, initial velocity vector is,

$u^{->}$ = 20 cos 30° i^ + 20 sin 30° j^

$u^{->}$ = 10√3 i^ + 10 j^

=> After 0.5 s, velocity vector is,

$v^{->}$ = 20 cos 30° i^ + {20 sin 30° - gt} j^

$v^{->}$ = 10√3 i^ + {10 - 5} j^

$v^{->}$ =  10√3 i^ + 5 j^

=> Thus, Change in velocity:

Δ$v^{->}$  = $v^{->}$ - $u^{->}$  = -5 j^

=> Thus, the magnitude of change in velocity in 0.5 second is,

|Δ$v^{->}$| = 5 m/s