Question

A particle is projected horizontal with a speed of 20m/sec from the top of a tower, after what time velocity of particle will be at 45° angle from initial velocity of the body​

Answer 1

Answer:

Correct option is

B

2s

At t=0

Ux=20m/s

vy=0 m/s

At given time

Vx=20m/s

Vy=gt=10 t m/s

tan450=vyvx

⇒10t20=1

t=2