a particle is projected horizontally with a speed [u] from the top of plane inclined at an angle theta with the horizontal . how far from the point of projection will the particle strike the plane ?
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aarviraghav5:
tnx for your practise to do this silution but the answer is not correct so . the answer is
D=2u {square over u}
D= 2u {square over u}/g tand theta sec theta
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