a particle is projected in upward direction with initial velocity vo. the height attained by the particle in time t is H=vot-1/2gt^2 ,where g is acceleration due to gravity. mark the correct sentence(s).
(a) H is maximum at t=vo/g
(b) H is zero at t=2vo/g
(c) the maximum value of H is v^2o/2g
(d) H is maximum at t=2vo/g
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Answer:
both options B and C are correct.
Explanation:
from the given formula
we can multiply thru by 2
i.e
2H = 2vot - gt²
divide thru by t
we have 2H/t = 2vo - gt
where H = 0
gt = 2vo
t = 2vo/g
and that proves statement B correct.
for validity of C, use Newton's third law of motion to get the answer.
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