Question

a particle is projected in vertical plane follows the plane ​

Answer 1

Answer:

Equation of trajectory of an projectile which is projected at some angle with horizontal is given by

y = xtan\theta(1 - \frac{x}{R})

here

\theta = angle with horizontal

R = horizontal range

now we have equation given as

3y = 4x - 15x^2

now we have

3y = 4x(1 - \frac{15x}{4})

y = \frac{4}{3}x (1 - \frac{x}{0.267})

now if we compare it with the equation of trajectory then we will have

tan\theta = \frac{4}{3}

R = 0.267 meter

so range of the projecti