Question

a particle is projected in x -y plane with gravity along -y direction. its equation of motion is given by y=bx-cx^2. find the range of the projectile

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Answer 1

Explanation:

A particle is projected from origin in xy-plane and its equation ,of trajectory is given by y = ax - bx^(2) . The only acceleration ,in the motion is' f' which is constant and in -ve direction of, y-axis. <br> (a) Find the velocity of projection and the angle of projection. <br> (b) Point of projection is considered as origin and x-axis along the horizontal ground. Find the horizontal range: and maximum height of projectile. Projectile completes its flight in horizonal plane of projection.