Question

A particle is projected making an angle 60 degree with the horizontal with kinetic energy to what is its kinetic energy at the highest

Answer 1

Hi buddy

let u be the initial velocity.
∴ initial kinetic energy is K = (1/2)mu²
at the maximum height velocity is u cos60 = (u/2)
∴ kinetic energy at the maximum height is KE=(1/2)m(u/2)²
=(1/4)k
Hope it helsp

Answer 2

Answer:

the answer is k/4

Explanation:

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