Question

a particle is projected so that it attains maximum height 25 what is maximum range of projectile​

Answer 1

Explanation:

maximum height can be attained only when the projectile is launched at 90°

therefore ,

h= u^2/2g

25×2×9.8= u^2

490=u^2

7√10=u

then for range ,

the maximum range occurs at 45°

R = u^2/g

R = 490/9.8

R = 50 m