Physics, asked by ritvik586, 1 month ago

A particle is projected up from the bottom of a hollow wedge of inclination 30°, with a velocity 40 root 2 ms^-1 at 45° to horizontal. (Take point of projection as origin, horizontal direction as x-axis and vertical direction as y-axis). There is a hole to the surface of wedge at (240 m, 60 m). This particle passes through that hole. If the base length of wedge is 280 m, the speed with which the particle hits the vertical face of the wedge is 10x ms^-1. Then x= (Take g=10ms^-2)​

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Answered by py774405
0

Answer:

horizontal line and we will friend

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