Question

a particle is projected up the ground with a speed of 25m/s it is at hight 30m at t1 and t2 find t1+t2 pls answerfast

Answer 1

Explanation:

t1+t2=5

Explanation:

In the question,

The speed of the projection of the particle is = 25 m/s

The height at which the particle is at times t, and t, is 30 m.

So,

Now we know that,

ut + 1\2at(Second equation of motion)

So,

30 = (25)+ - (10) So, 12 = 10t – 2+2 6 = 5t - t

t2 – 5t +6 = 0 So, (t - 3)(t - 2) = 0 t=2,3

So,

t1=2 seconds

t2=3 seconds

So,

t,+t,=2+3=5 seconds

So,

t1+t2=5

Therefore, the sum of the time at which the particle is at the same height is 5 seconds.