Question

A particle is projected up to air with a speed of 20 m/s at an angle of projection 30* .what is the maximum height reached by it

Answer 1

u²sin²x/2g

20² 0.5²/2*9.8

400*0.25/19.6

100/19.6

5.102

Answer 2

Answer:

The maximum height reached by the particle is 10m.

Explanation:

For a projectile motion, maximum height is calculated as,

$H=\frac{u^2 sin^2\theta}{2g}$        (1)

Where,

H=maximum height attained

u=velocity of the projected particle

θ=angle of projection

g=acceleration due to gravity=10m/s²   (constant)

From the question we have,

u=20m/s

θ=30°

sin30°=1/2

By substituting the value of u,sin30°, and g in equation (1) we get;

$H=\frac{(20)^2 \frac{1}{2}}{2\times 10}=10m$

Hence, the maximum height reached by the particle is 10m.