Question

a particle is projected up with speed 50 m/s what is it's time of motion and maximum height achieved​

Answer 1

a particle is projected up with speed 50 m/s

u = 50 m/s (upward)

g = 10 m/s² (downward)

time of motion, t = 2u / g = 2×50/10 = 10s

maximum height achieved​:

$h_{max}=\frac{u^2}{2g}=\frac{50^2}{2 \times 10} = \frac{2500}{20}=125\ m$

Answer 2

Answer:time taken=2u/g=2*50/10=10 s

max height=u*u/2g=2500/20=125 m

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