A particle is projected upward with speed, v. Speed (u) of body on reaching the point from which it was projected, is
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0
Answer:
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4
Answer:
If h is the maximum height then h= 2gu 2
Time taken to reach height h, t= gu
Let v be the speed at
43h
then v 2
=u 2
−2g( 43h)⇒v= 2u
let be the time taken to reach
43h
then
2u
=u−gt ′
⇒t ′
= 2gu
= 2t
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