A particle is projected upwards with a velocity of 100m/s at an angle of 60°with the vertical. Find the time when the particle will move perpendicular to its initial direction,taking g=10m/s2
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Explanation:
u=100sin60
0
i
^
+100cos60
0
j
^
=50
j
^
+50
3
i
^
v
=
u
−gt
j
^
=50
j
^
+50
3
i
^
−10t
j
^
=50
3
i
^
+(50−10t)
j
^
When velocity is perpendicular to initial velocity,
v
.
u
=0, or (50
3
i
^
+(50−10t)
j
^
).(50
j
^
+50
3
i
^
)=0 or, 7500+2500−500t=0
which gives, t=20s
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