A particle is projected upwards with velocity 60 metre per second in 8 seconds the average speed and average velocity of the particle is
Answers
Average speed and Average velocity are same=100m/s
x(t)=x' + v'(t) + 0.5a(t^2)
x(t)=0+60(8)+5(64)
x(t)=800m
Avg velocity=displacement/time
=800/8
=100m/s
Since it's moving in straight line so displacement and distance are equal, so avg velocity and avg speed are also equal.
Answer:
Explanation:
Since, the particle is projected upwards at highest point the final velocity v will be 0.
From equation, v=u-at
0= 60-10t
60=10t =>> [ t=6 s]
And from equation, v²=u²-2gh
0=(60)²-2×10×h
3600=20h =>> [h=180m]
Therefore, it is clear that in 6 sec the particle will achieve its maximum height.
Now from equation ,s=ut+½at²
s=60×0 +½×10×2² =>> s=½×10×4
=>> s=20m
Hence, displacement=180-20=160m
So, average velocity = displacement/time
V=160/8
[V=20 m/s]
Distance = 180+20=>200m
Average speed = distance /time
S=200/8
[S=25m/s]