Question

A particle is projected vertically up from the top of a tower with velocity 10 m/s. It reaches the ground in 5s. Find Height of the tower.
Please help to solve this question....​

Answer 1

Answer:

175m

Explanation:

Given,

initial velocity (u)=10m/s

time taken to reach the ground (t)=5s

height of tower (h)=?

Then,We know

s=ut + 1/2 gt^2 [as a=g}

So, h= 10*5 + 1/2*10*(5)^2

         =50 + 125

         =175m